$(a)\;17.35L\qquad(b)\;16.081L\qquad(c)\;16L\qquad(d)\;17.5L$

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Meq of HCl required=$45000\times 4.360$

$\Rightarrow 196200$

$\therefore \large\frac{w_{HCl}}{36.5}$$\times 1000=196200$

$w_{HCl}=7161.3g$

$37.5g$ HCl are present in 100g solution

$7161.3g$ HCl are present in $\large\frac{100\times 7161.3}{37.5}$

$\Rightarrow 19096.8g$ solution.

Volume of solution=$\large\frac{\text{Wt of solution}}{\text{density of solution}}$

$\Rightarrow \large\frac{19096.8}{1.1875}$

$\Rightarrow 16081.5ml$

$\therefore 16.081L$

Hence (b) is the correct answer.

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