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1g sample of washing soda was dissolved in 50ml of 1.0M HCl.The excess acid required for neutralization 21.13ml of 1.018M $Ba(OH)_2$.Compute the degree of hydration of washing soda.

$(a)\;11\qquad(b)\;12\qquad(c)\;9\qquad(d)\;10$

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Meq of HCl added to washing soda=$50\times 1=50$
Meq of HCl left,(i.e) used by $Ba(OH)_2$
$\Rightarrow $ Meq of $Ba(OH)_2$
$\Rightarrow 21.13\times 1.018\times 2$
$\Rightarrow 43.02$
Meq of HCl used for washing soda$=50-43.02$
$\Rightarrow 6.98$
Meq of HCl washing soda $(Na_2CO_3-xH_2O)$=6.98
$\large\frac{w}{\Large\frac{M}{2}}$$\times 1000=6.98$
$w=1g$
$\therefore M=286.5$
Mol wt of $Na_2CO_3xH_2O=46+60+18x=106+18x$
$106+18x=286.5$
$x=10$
$\therefore$ Degree of hydration=10
Hence (d) is the correct answer.
answered Jan 8, 2014 by sreemathi.v
 

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