Let 'a'g and 'b'g are weights of Al and Zn in mixture
$a+b=1.67$--------(1)
Meq of Al+Meq of Zn=Meq of $H_2$
$\large\frac{a}{\Large\frac{27}{3}}$$\times 1000+\large\frac{b}{\Large\frac{65}{2}}$$\times 1000=\large\frac{1.69}{\Large\frac{22.4}{2}}$$\times 1000$-----(2)
From equation (1) & (2)
$a=1.25g\qquad Al$
$b=0.42g\qquad Zn$
Hence (a) is the correct answer.