Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A sample of chalk $(CaCO_3)$ is contaminated with calcium sulphate $(CaSO_4)$ 1gm of the solid mixture is dissolved in 230ml of N/10 HCl; 40ml of N/10 NaOH is required to neutralize the excess of acid.Find the percentage of chalk in the mixture.


Can you answer this question?

1 Answer

0 votes
Volume of HCl used against $CaCO_3$ is not given.
Excess of HCl is neutralized by NaOH
$\Rightarrow \big(\large\frac{1}{10}\big)$$\times V_1=\big(\large\frac{1}{10}\big)$$\times 40$
$V_1=40ml$=Volume of excess HCl
Volume of HCl used for $CaCO_3=230-40=190cc$
Meq of HCl=Meq of $CaCO_3$
$\large\frac{1}{10}$$\times 190=\large\frac{g}{E}$$\times 1000$
g=0.95=95% Pure carbonate.
Hence (a) is the correct answer.
answered Jan 8, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App