Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The capacitors A and B are connected in series with a battery. When S is closed two capacitor gets fully charged , then :


(A) Ratio of charges on A and B is 3:2

(B)Ratio of electrical energies stored in A and B is 2:3

(C)The potential difference across A is 6 V and across B is 4V

(D)The potential difference across A is 4 V and across B is 6V

Can you answer this question?

1 Answer

0 votes
Total capacitance in series $=\large\frac{20 \times 30}{20+30}$
$\qquad= 12 \mu F$
$Q= CV$
$\quad= 12 \times 10= 120 \mu C$
$V_A= \large\frac{Q}{C_A} =\frac{120}{20}$$=6V$
$V_B= \large\frac{Q}{C_B} =\frac{120}{30}$$=4V$
Hence C is the correct answer.
answered Jan 8, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App