logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

25ml of a solution containing HCl and $H_2SO_4$ required for neutralized 24.10ml of N/2 caustic soda solution.25ml of the same solution on precipitation with $BaCl_2$ yielded 0.5218gm $BaSO_4$.What wt of each acid is contained in one litre of the solution?

$(a)\;10.5g/l,9.5g/l\qquad(b)\;11.05g/l,8.76g/l\qquad(c)\;10.25g/l,10g/l\qquad(d)\;12g/l,7g/l$

Can you answer this question?
 
 

1 Answer

0 votes
Caustic soda reacts with both HCl and $H_2SO_4$ whereas $BaCl_2$ reacts with only $H_2SO_4$ to precipitate out $BaSO_4$
Meq of $H_2SO_4$=Meq of $BaSO_4$
Meq of $H_2SO_4=\large\frac{0.5218}{\Large\frac{233.4}{2}}$$\times 1000=4.47$
(E of $BaSO_4=\large\frac{233.4}{2})$
Let $x=$Meq of HCl in the sample
(Meq of HCl+Meq of $H_2SO_4$)=Meq of $NaOH$
$\Rightarrow x+4.47=\large\frac{1}{2}$$\times 24.10\Rightarrow x=7.58$
$\Rightarrow \large\frac{g}{36.5}$$\times 1000=7.58$
$\Rightarrow g=0.2767gm$
This is the wt of HCl in 25ml
Wt of HCl in 1L=$\large\frac{1000}{25}$$\times 0.2767$
$\Rightarrow 11.05g/l$
Similarly,mass of $H_2SO_4$ from this meq=(4.47),in 1L of sample=8.76g/l
Hence (b) is the correct answer.
answered Jan 8, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...