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# $4I^-+Hg^{2+}\rightarrow HgI_4^{2-}$;1 mole each of $Hg^{2+}$ and $I^-$ will form _________ mole $HgI_4^{2-}$

$(a)\;1mole\qquad(b)\;0.5mole\qquad(c)\;0.25mole\qquad(d)\;2mole$

4 mole of $I^{-}$ will give 1 mole of $HgI_4^{2-}$ with one mole of $Hg^{2+}$
$\therefore$ The mole ratio order is 4 : 1 : 1
$\therefore$ 1 mole of $I^-$ form 0.25mole of $HgI_4^{2-}$
Hence (c) is the correct answer.