Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A charge Q and another charge q are placed at two points A and B which are distance l apart. Keeping q stationary at B, Q is moved to point C such that ABC forms equilateral triangle of side l. Find the net work done ?

$(A)\;\frac{1}{4 \pi \in_0} \frac{Qq}{l} \\ (B)\;\frac{1}{4 \pi \in_0} \frac{Qq}{l^2} \\ (C)\;Zero \\ (D)\;\frac{1}{4 \pi \in_0} Qql $

Can you answer this question?

1 Answer

0 votes
Potential at A and C are equal , therefore work done in moving Q from A to C is zero.
Hence C is the correct answer.
answered Jan 8, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App