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Number of $K^+$ ions present in one litre of M/5 $KMnO_4$ solution are :

$\begin{array}{1 1}(a)\;10\times 10^{24}&(b)\;1.204\times 10^{23}\\(c)\;6.02\times 10^{23}&(d)\;3.01\times 10^{24}\end{array}$

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Milli-mole of $KMnO_4=1000\times \large\frac{1}{5}$$=200$
$\therefore$ 1 mole of $KMnO_4$ has N $K^+$ ion
$\therefore 0.2$ mole of $KMnO_4$ has $0.2\times N\;K^+$ion
$\Rightarrow 0.2\times 6.02\times 10^{23}$
$\Rightarrow 1.204\times 10^{23}$
Hence (b) is the correct answer.
answered Jan 8, 2014 by sreemathi.v

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