Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Number of $K^+$ ions present in one litre of M/5 $KMnO_4$ solution are :

$\begin{array}{1 1}(a)\;10\times 10^{24}&(b)\;1.204\times 10^{23}\\(c)\;6.02\times 10^{23}&(d)\;3.01\times 10^{24}\end{array}$

Can you answer this question?

1 Answer

0 votes
Milli-mole of $KMnO_4=1000\times \large\frac{1}{5}$$=200$
$\therefore$ 1 mole of $KMnO_4$ has N $K^+$ ion
$\therefore 0.2$ mole of $KMnO_4$ has $0.2\times N\;K^+$ion
$\Rightarrow 0.2\times 6.02\times 10^{23}$
$\Rightarrow 1.204\times 10^{23}$
Hence (b) is the correct answer.
answered Jan 8, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App