$(A)\;22 \times 10^{-6} J \\ (B)\;88 \times 10^{-6} J \\ (C)\; \frac{64}{3} \times 10^{-6} J\\ (D)\;\frac{32}{3} \times 10^{-6} J $

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Equivalent capacitance $=\large\frac{C_1C_2}{C_1+C_2} +C_3$

$\qquad= \large\frac{4 \times 12}{4+ 12} $$+8$

$\qquad= 11 \mu F$

$Q= CV$

$ \quad= 11 \times 10^{-6} \times 4= 44 \times 10^{-6}V$

$W= \large\frac{1}{2} $$QV=\large\frac{1}{2}$$ \times 44 \times 10^{-6} \times 4$

$\quad= \large\frac{1}{2}$$ \times 44 \times 10^{-6} \times 4$

$\quad= 88 \times 10^{-6} J$

Hence B is the correct answer.

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