$(A)\;25 \\ (B)\;\frac{1}{25} \\ (C)\; 1 \\ (D)\;125 $

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Potential on small drop (V) $=\large\frac{1}{4 \pi \in _0} \frac{q}{r}$

Volume of 125 small drops = Volume of big drop

=> $125 \times \large\frac{4}{3} \pi r^3= \large\frac{4}{3}$$\pi R^3$

=> $ R= 5r$

Potential on big drop,

$V'= \large\frac{1}{4 \pi \in _0} \frac{Q}{R}$

$\quad= \large\frac{1}{4 \pi \in _0} \frac{125 q}{5r}$

$\quad=25 V$

Hence A is the correct answer.

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