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A charge q is placed at centre of cube of side l. The electric flux through one face of cube will be :

$(A)\;\frac{a}{\in_0} \\ (B)\;\frac{q}{6 \in _0} \\ (C)\; \frac{q}{3 \in _0} \\ (D)\;None $

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If charge is placed in the centre of cube,
flux through  surface of cube is $6\phi$ , where $\phi$ is flux through each face.
by Gauss's law,
$6 \phi =\large\frac{q}{\in _0}$
=> $ \phi =\large\frac{q}{6 \in _0}$
Hence B is the correct answer.


answered Jan 8, 2014 by meena.p
edited Jul 31, 2014 by thagee.vedartham

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