# What is effective capacitance between A and B

$(A)\;C \\ (B)\;\frac{5}{3}C \\ (C)\; \frac{3}{5}C \\ (D)\;None$

$C_{23} =C_2 +C_3$
$\qquad= C+ C$
$\qquad= 2C$
$C_{123} =\frac{ C_1 \times C_23}{C_1 + C_23}= \large\frac{C \times 2C}{3C}$
$C_{AB}=C_{123} +C_4$
$\qquad= \large\frac{2C}{3} +c$
$\qquad= \large\frac{5C}{3}$
Hence B is the correct answer.
answered Jan 8, 2014 by