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If $0.5$ mole of $BaCl_2$ is mixed with 0.2 mole of $Na_3PO_4$,the maximum number of moles of $Ba_3(PO_4)_2$ that can be formed is :

$(a)\;0.7\qquad(b)\;0.5\qquad(c)0.30\qquad(d)\;0.1$

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$3BaCl_2+2Na_3PO_4\rightarrow Ba_3(PO_4)_2+6NaCl$
Initial: $3BaCl_2\Rightarrow 0.5,2Na_3PO_4\Rightarrow 0.2,Ba_3(PO_4)_2\Rightarrow 0,6Nacl\Rightarrow 0$
final: $3BaCl_2\Rightarrow (0.5-0.3),2Na_3PO_4\Rightarrow 0,Ba_3(PO_4)_2\Rightarrow 0.1,6Nacl\Rightarrow 0.6$
Hence (d) is the correct answer.
answered Jan 8, 2014 by sreemathi.v
 

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