logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
0 votes

An unbiased die with faces marked 1,2,3,4,5 and 6 is rolled four times out of four values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is :

$\begin {array} {1 1} (A)\;\large\frac{16}{81} & \quad (B)\;\large\frac{1}{81} \\ (C)\;\large\frac{80}{81} & \quad (D)\;\large\frac{65}{81} \end {array}$

 

Can you answer this question?
 
 

1 Answer

0 votes
Favourable points are 2,3,4,5
$ \therefore P = \large\frac{4}{6} = \large\frac{2}{3}$
Since the die is rolles 4 times
$ \therefore $ Required probability = $ \bigg( \large\frac{2}{3} \bigg)^4$
$ = \large\frac{16}{81}$
answered Jan 8, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...