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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

If the probability for A to fail in an examination is 0.2 and that for B is 0.3 then the probability that either A or B fails is

$\begin {array} {1 1} (A)\;0.38 & \quad (B)\;0.44 \\ (C)\;0.50 & \quad (D)\;0.94 \end {array}$

 

1 Answer

$ P( \overline A) = 0.2$
$P(A) = 1-0.2$
= $ 0.8$
$ P( \overline B) = 0.3$
$P(B) = 1-0.3 = 0.7$
$P( \overline A \cup \overline B) = P( \overline {A \cap B })$
$ = 1-P(A \cap B )$
$ 1-P(A)\: P(B)$
$1-(0.8)(0.7)$
$ = 0.44$
Ans : B
answered Jan 8, 2014 by thanvigandhi_1
 

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