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For the reaction :$A+2B\rightarrow C$,5 mole of A and 8 mole of B will produce

$(a)\;5\;mole\;of\;C\qquad(b)\;4\;mole\;of\;C\qquad(c)\;8\;mole\;of\;C\qquad(d)\;13\;mole\;of\;C$

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$A+2B\rightarrow C$
initial : $A\Rightarrow 5,2B\Rightarrow 8,C\Rightarrow 0$
Final : $A\Rightarrow 5-4,2B\Rightarrow 0,C\Rightarrow 4$
Hence (b) is the correct option
answered Jan 8, 2014 by sreemathi.v
 

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