$\begin {array} {1 1} (A)\;\large\frac{5}{64} & \quad (B)\;\large\frac{27}{32} \\ (C)\;\large\frac{5}{32} & \quad (D)\;\large\frac{1}{2} \end {array}$

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To satisfy the condition of the problem, first 6 draws should give exactly

3 white balls and 7th draw should give a white ball.

Hence the required probability is $ = 6C_3 \bigg(\large\frac{1}{2}\bigg)^3 \bigg(\large\frac{1}{2}\bigg)^3 \times \large\frac{1}{2}$

$ = \large\frac{20}{128}$

$ = \large\frac{5}{32}$

Ans : (C)

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