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The % loss in weight after heating a pure sample of potassium chlorate (M wt:122.5) will be

$(a)\;12.25\qquad(b)\;24.50\qquad(c)\;39.17\qquad(d)\;49.00$

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1 Answer

$2KClO_3\rightarrow 2KCl+3O_2$
$2\times 122.5$ shows a wt loss of $3\times$ 32g $O_2$
100g shows a wt loss=$\large\frac{3\times 32\times 100}{2\times 122.5}$
$\Rightarrow 39.17$
Hence (c) is the correct answer.
answered Jan 8, 2014 by sreemathi.v
 

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