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25ml of 3.0M $HNO_3$ are mixed with 75ml of 4.0M $HNO_3$.If the volumes are additive,the molarity of the final mixture would be :


1 Answer

M-Mol of $HNO_3$=$25\times 3=75$
M-Mol of $HNO_3$=$75\times 4=300$
$\therefore$Total M-mol=375
This 375=$M\times 100$
$\therefore M=3.75$
Hence (c) is the correct answer.
answered Jan 8, 2014 by sreemathi.v

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