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Capacitors $C1$ and $C2$ are joined as shown below. If potential at point A i $V_A$ and point B is $V_B$, Potential at point C is

 

$(A)\;\frac{C2 V_A-C1 V_B}{C1+C2} \\ (B)\;\frac{C1 V_A+C2 V_B}{C1+C2} \\ (C)\; \frac{1}{2} (V_A+V_B) \\ (D)\;None $

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