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How many of $KCl$ would have to be dissolved in 60g $H_2O$ to give 20% by weight of solution?

$\begin{array}{1 1}(a)\;15g&(b)\;0.01g\\(c)\;0.5g&(d)\;0.244g\end{array}$

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% by weight=$\large\frac{\text{Wt of solute}}{\text{Wt of solution}}$$\times 100$
$20=\large\frac{w}{w+60}$$\times 100$
$w=15g$
Hence (a) is the correct answer.
answered Jan 9, 2014 by sreemathi.v
 

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