Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

An ore contains 2.0% by weight of the mineral argentive $(Ag_2S)$.How much of ore should be taken to produce 1.0g pure Ag?

$\begin{array}{1 1}(a)\;45.7g&(b)\;67.4g\\(c)\;57.4g&(d)\;87.6g\end{array}$

Can you answer this question?

1 Answer

0 votes
$216g$ Ag=$248g\; Ag_2S$ pure
$1g\;Ag=\large\frac{248}{216}$g $Ag_2S$
$\Rightarrow \large\frac{248}{216}\times \frac{100}{2}g$ impure $Ag_2S$
$\Rightarrow 57.4g$
Hence (c) is the correct answer.
answered Jan 9, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App