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An ore contains 2.0% by weight of the mineral argentive $(Ag_2S)$.How much of ore should be taken to produce 1.0g pure Ag?

$\begin{array}{1 1}(a)\;45.7g&(b)\;67.4g\\(c)\;57.4g&(d)\;87.6g\end{array}$

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$216g$ Ag=$248g\; Ag_2S$ pure
$1g\;Ag=\large\frac{248}{216}$g $Ag_2S$
$\Rightarrow \large\frac{248}{216}\times \frac{100}{2}g$ impure $Ag_2S$
$\Rightarrow 57.4g$
Hence (c) is the correct answer.
answered Jan 9, 2014 by sreemathi.v
 

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