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The ratio of specific charge (e/m) of a proton to that of an $\alpha$-particle is :

$(a)\;1 : 4\qquad(b)\;1 : 2\qquad(c)\;1 : 1/4\qquad(d)\;2 : 1$

1 Answer

e/m for proton =$\large\frac{1}{1}$
e/m for $\alpha$-particle =$\large\frac{2}{4}$
Hence (d) is the correct answer.
answered Jan 9, 2014 by sreemathi.v
 

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