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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
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A and B throw a dice each. The probability that A's throw is not greater than B's throw is

$\begin {array} {1 1} (A)\;\large\frac{7}{12} & \quad (B)\;\large\frac{5}{12} \\ (C)\;\large\frac{1}{6} & \quad (D)\;\large\frac{1}{2} \end {array}$

 

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1 Answer

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When A gets 1, B can get any of the numbers 1,2,3,4,5,6.
When A gets 2, B can get any of the numbers 2,3,4,5,6.
Favourable number of ways = 6+5+.....+1=21
Probability that A's throw is not greater than B's throw is $ \large\frac{21}{36}$
= $ \large\frac{7}{21}$
Hence (A) is the correct option.
answered Jan 15, 2014 by thanvigandhi_1
 

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