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If a point charge is placed at the centre of closed cylindrical conductor of length l and radius R. the flux through the cylinder will be :

$(A)\;zero \\ (B)\;\frac{ql}{2 \in _0 [R^2+l^2/4]^{1/2}} \\ (C)\; \frac{q}{\in _0} \\ (D)\;none $

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Since the cylinder is conducting therefore an equal and opposite charge $-q$ will get induced on inner surface of cylinder.
And hence net charge enclosed by surface become zero it makes the flux zero.
Hence A is the correct answer.


answered Jan 9, 2014 by meena.p
edited Aug 1, 2014 by thagee.vedartham

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