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The total number of fundamental particles in one atom of $_6 C ^{14}$ is

$(a)\;6\qquad(b)\;8\qquad(c)\;14\qquad(d)\;20$

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No of fundamental particles =6 protons + 6 electrons + 8 neutrons
$\Rightarrow 20$
Hence (d) is the correct answer.
answered Jan 10, 2014 by sreemathi.v
 

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