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The ratio between the neutrons present in carbon and silicon with respect to mass number of 12 and 28 respectively is

$(a)\;3 : 7\qquad(b)\;7 : 3\qquad(c)\;3 : 4\qquad(d)\;6 : 28$

1 Answer

Carbon is $_6 C ^{12}$ and silicon is $_{14} Si ^{28}$
Hence (a) is the correct answer.
answered Jan 10, 2014 by sreemathi.v
 

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