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Which orbital is nearest to the nucleus?

$(a)\;5d\qquad(b)\;6s\qquad(c)\;6p\qquad(d)\;4f$

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$4^{th}$ shell is more closer.No doubt its energy may be more.
Hence (d) is the correct answer.
answered Jan 10, 2014 by sreemathi.v
 

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