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The number of d-electrons present in $Fe^{2+}$ is

$(a)\;5\qquad(b)\;6\qquad(c)\;3\qquad(d)\;4$

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$Fe^{2+}$ is $1s^2,2s^22p^6,3s^23p^63d^6$
Hence (b) is the correct answer.
answered Jan 10, 2014 by sreemathi.v
 

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