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Magnetic moments of $V(Z=23), \;Cr(Z=24),\;Mn(Z=25)$ are $x,\;y,\;z$ , respectively. Hence,

$(a)\;x=y=z\qquad(b)\;x < y < z\qquad(c)\;x < z < y\qquad(d)\;z < y < x$

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  • Magnetic moment, $\mu \;= \; \sqrt{n(n+2)}$, where, n = number of unpaired electrons.
$V,\;Cr,\;Mn$ have three, six and five unpaired electrons, respectively.
$\therefore$ Magnetic moments of $V, \;Cr$ and $Mn$ are 3.873, 6.928 and 5.916, respectively.
Hence (c) is the correct answer.
answered Jan 10, 2014 by sreemathi.v
edited Apr 2, 2014 by mosymeow_1

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