Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two infinite long parallel wires having linear charge densities $\lambda_1\; and\; \lambda_2 $ respectively are placed at a distance R. The force per unit length on wire (1) will be:

$(A)\;\frac{K 2 \lambda_1 \lambda_2}{R} \\ (B)\;K \frac{2 \lambda_1^2}{R} \\ (C)\; Zero \\ (D)\;none $

Can you answer this question?

1 Answer

0 votes
Electric field due to wire (2)$= \large\frac{1}{4 \pi \in _0} \frac{2 \lambda_2}{R}$
Charge per unit length on wire $(1)=\lambda _2$
Force per unit length on wire $(1) =\lambda_1 \times E$
$\qquad= \lambda \times \large\frac{1}{4 \pi \in _0}\frac{2 \lambda_2}{R}$
$\qquad= \large\frac{K(2 \lambda _1 \lambda_2)}{R}$
Hence A is the correct answer.
answered Jan 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App