logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Two infinite long parallel wires having linear charge densities $\lambda_1\; and\; \lambda_2 $ respectively are placed at a distance R. The force per unit length on wire (1) will be:

$(A)\;\frac{K 2 \lambda_1 \lambda_2}{R} \\ (B)\;K \frac{2 \lambda_1^2}{R} \\ (C)\; Zero \\ (D)\;none $

Can you answer this question?
 
 

1 Answer

0 votes
Electric field due to wire (2)$= \large\frac{1}{4 \pi \in _0} \frac{2 \lambda_2}{R}$
Charge per unit length on wire $(1)=\lambda _2$
Force per unit length on wire $(1) =\lambda_1 \times E$
$\qquad= \lambda \times \large\frac{1}{4 \pi \in _0}\frac{2 \lambda_2}{R}$
$\qquad= \large\frac{K(2 \lambda _1 \lambda_2)}{R}$
Hence A is the correct answer.
answered Jan 10, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...