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# In ground state of $_{24}Cr$

(a) 13 electrons have spin in one direction and 11 electrons in other direction
(b) 14 electrons have spin in one direction and 10 electrons in other direction
(c) 15 electrons have spin in one direction and 9 electrons in other direction
(d) 15 electrons have clockwise direction and 9 electrons in anti clockwise direction

$_{24}Cr$ is: $1s^2,2s^22p^6,3s^23p^63d^5,4s^1$ 15 electrons in one direction (may be clockwise or anti clock wise) and 9 electron in other direction.
Hence (c) is the correct answer.