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Three identical metal plates are kept parallel to one another at seperation $d_1\; and\; d_2 $ If both the outer plates are connected to ground and middle plate is given charge q, The charge on right side of middle plate will be :

$(A)\;\frac{q}{2} \\ (B)\;\frac{qd_1}{d_1+d_2} \\ (C)\; \frac{qd_2}{d_1+d_2} \\ (D)\;none $

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$V= \large\frac{Q_1}{c_1}=\frac{Q_2}{C_2}$
$C_1 =\large\frac{\in _0 A}{d_1}$
$C_2 =\large\frac{\in _0 A}{d_2}$
=> $Q_2 =\large\frac{q d_1}{d_1+d_2}$
Hence b is the correct answer.


answered Jan 10, 2014 by meena.p
edited Aug 1, 2014 by thagee.vedartham

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