$(A)\;15 v \\ (B)\;8.5 v \\ (C)\; 10 v \\ (D)\;0V $

If Q is the charge flowing.

By Kirchhoff 's law,

$V_A-\large\frac{Q}{C_1} $$+E-\large\frac{Q}{C_2}$$=V_B$

=> $V_A-V_B+E= Q \bigg( \large\frac{1}{C_1}+\frac{1}{C_2}\bigg)$

=> $5+10= Q \bigg( \large\frac{C_1+C_2}{C_1C_2}\bigg)$

=> $\qquad= Q \bigg( \large\frac{2+2}{2 \times 2}\bigg)$

=>$Q= 15 \mu c$

V across $C_2 =\large\frac{15 \mu C}{2 \mu F}$

$\qquad =7.5 V$

Hence B is the correct answer.

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