(A)Decrease

(B)Remains same

(C)Increase

(D)becomes infinite

On placing thin metal sheet

$C_1=\large\frac{A \in _0}{x}$

$C_2=\large\frac{A \in _0}{d-x}$

$C_{eq}=\large\frac{C_1C_2}{C_1+C_2}$

$\qquad= \large\frac{\Large\frac{\in _0 A}{x} . \Large \frac {\in _0 A}{d-x}}{\Large\frac{\in _0 A}{x} +\Large\frac{\in _A}{d-x}}$

$\qquad=> C_{eq} =\large\frac{\in _0 A}{d}$

C remains unchanged

Hence B is the correct answer.

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