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A thin metal sheet is placed between the plates of a parallel plate capacitor. Its capacitance will


(B)Remains same


(D)becomes infinite

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On placing thin metal sheet
$C_1=\large\frac{A \in _0}{x}$
$C_2=\large\frac{A \in _0}{d-x}$
$\qquad= \large\frac{\Large\frac{\in _0 A}{x} . \Large \frac {\in _0 A}{d-x}}{\Large\frac{\in _0 A}{x} +\Large\frac{\in _A}{d-x}}$
$\qquad=> C_{eq} =\large\frac{\in _0 A}{d}$
C remains unchanged
Hence B is the correct answer.
answered Jan 10, 2014 by meena.p

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