Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

In the circuit given below, the position of switch S is shifted from 1 to 2 . choose the correct statement



(A)Heat generated in the circuit is $\large\frac{1}{2}$$ CE_1E_2$

(B)Heat generated in the circuit is $\large\frac{1}{2} $$CE_2^2$

(C)A charge of amount $CE_2 $ will be supplied by battery $E_1$

(D)A charge of amount $CE_2 $ will be supplied by battery $E_2$

Can you answer this question?

1 Answer

0 votes
When switch is at position 1, C is connected in series with $E_1\; and\; E_2$
$Q_i= C( E_2 -E_1)$
When switch is moved to position 2, $Q_f= -E_1C$
$\Delta Q= Q_f -Q_i =-C E_2$
Net +ve charge pulled by battery $(E_1)= CE_2$
Work done in process of charge transfer $=CE_1E_2=\Delta w$
Change in energy of the capacitance
$ \Delta W_c=\large\frac{q_f^2}{2C} -\frac{Q_i ^2}{2C}$
$\qquad= \large\frac{1}{2}$$ E_1^2 C -\large\frac{1}{2}$$ (E^2-E_1)^2 C$
$\qquad= \large\frac{1}{2} $$(2 E_1 E_2-E_2^2)C$
Remaining part is lost as heat
$H= \Delta W- \Delta W_c$
$\quad= \large\frac{1}{2} {E_2}^2 C$
Hence B is the correct answer.


answered Jan 10, 2014 by meena.p
edited Aug 1, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App