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Uncertainty in position of a minute particle of mass 25g in space is $10^{-5}$m.The uncertainty in its velocity (in $ms^{-1})$ is

$\begin{array}{1 1}(a)\;2.1\times 10^{-34}&(b)\;0.5\times 10^{-34}\\(c)\;2.1\times 10^{-28}&(d)\;0.5\times 10^{-23}\end{array}$

1 Answer

$\Delta u=\large\frac{h}{4\pi m.\Delta x}$
$\Rightarrow \large\frac{6.626\times 10^{-34}}{4\times 3.14\times 25\times 10^{-3}\times 10^{-5}}$
$\Rightarrow 2.1\times 10^{-28}$m/sec
Hence (c) is the correct answer.
answered Jan 13, 2014 by sreemathi.v
 

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