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In a multi-electron atom,which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic field.\[\] $\begin{array}{1 1}(i)\;n=1,l=0,m=0\\(ii)\;n=2,l=0,m=0\\(iii)\;n=2,l=1,m=1\\(iv)\;n=3,l=2,m=1\\(v)\;n=3,l=2,m=0\end{array}$

$\begin{array}{1 1}(i)\;n=1,l=0,m=0\\(ii)\;n=2,l=0,m=0\\(iii)\;n=2,l=1,m=1\\(iv)\;n=3,l=2,m=1\\(v)\;n=3,l=2,m=0\end{array}$

$\begin{array}{1 1}(a)\;(i)\;and\;(ii)\\(b)\;(ii)\;and(iii)\\(c)\;(iii)\;and\;(iv)\\(d)\;(iv)\;and\;(v)\end{array}$

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Orbitals having (n+l) same possess same energy in absence of magnetic field.
Hence (d) is the correct answer.
answered Jan 13, 2014 by sreemathi.v
 

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