$\begin{array}{1 1}(a)\;1.52\times 10^{-4}m&(b)\;5.10\times 10^{-3}m\\(c)\;1.92\times 10^{-3}m&(d)\;3.84\times 10^{-3}m\end{array}$

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$u=600 msec^{-1}$

$\therefore \Delta u=\large\frac{600\times 0.005}{100}$

$\Rightarrow 0.30msec^{-1}$

Now,$\Delta x.m.\Delta u=\large\frac{h}{4\pi}$

$\Delta x=\large\frac{6.6\times 10^{\large-34}}{4\times 3.14\times 9.1\times 10^{\large-31}\times 0.30}$

$\Rightarrow 1.92\times 10^{-3}m$

Hence (c) is the correct answer.

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