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A 3p-orbital has :

$\begin{array}{1 1}(a)\;\text{Two spherical nodes}\\(b)\;\text{Two non-spherical nodes}\\(c)\;\text{One spherical and one non-spherical node}\\(d)\;\text{One spherical and two non-spherical node}\end{array}$

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Spherical node =$n-l-1=3-1-1=1$
Non spherical node =$l=1$
Hence (c) is the correct answer.
answered Jan 13, 2014 by sreemathi.v
 

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