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The energy of an electron in the first orbit of H-atom is -13.6eV.The possible value of excited state for electron in bohr orbit of H atom are :

$(a)\;-3.4eV\qquad(b)\;-4.2eV\qquad(c)\;-6.8eV\qquad(d)\;6.8eV$

1 Answer

$E_n=\large\frac{E_1}{n^2}$
$\Rightarrow \large\frac{-13.6}{2^2}$
$\Rightarrow -3.4eV$
Hence (a) is the correct answer.
answered Jan 15, 2014 by sreemathi.v
 

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