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If the nitrogen atom had electronic configuration $1s^7$,it would have energy lower than that of normal ground state configuration $1s^22s^22p^3$,because the electrons would be closer to the nucleus.Yet $1s^7$ is not observed because it violates

$\begin{array}{1 1}(a)\;\text{Heisenberg's uncertainty principle}\\(b)\;\text{Hund's rule}\\(c)\;\text{Pauli exclusion principle}\\(d)\;\text{Bohr postulate of stationary orbits}\end{array}$

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Pauli proposed that s-orbitals cannot have more than two electron.
Hence (c) is the correct answer.
answered Jan 15, 2014 by sreemathi.v

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