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The number of radial nodes of 3s and 2p orbitals are respectively

$\begin{array}{1 1}(a)\;2,0&(b)\;0,2\\(c)\;1,2&(d)\;2,1\end{array}$

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Number of radial nodes =$n-l-1$
For $3s$ it is 2
For $2p$ it is 0
Hence (a) is the correct answer.
answered Jan 15, 2014 by sreemathi.v

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