$\begin{array}{1 1}(a)\;37.5\times 10^{18}&(b)\;28.6\times 10^{12}\\(c)\;27.2\times 10^{18}&(d)\;32.3\times 10^{14}\end{array}$

Energy of one photon =$\large\frac{hc}{\lambda}$

$\Rightarrow \large\frac{6.625\times 10^{-34}\times 3\times 10^8}{4500\times 10^{-10}}$

$\Rightarrow 4.42\times 10^{-19}J$

Energy emitted by bulb=$150\times \large\frac{8}{100}$J

$\therefore n\times 4.42\times 10^{-19}=150\times \large\frac{8}{100}$

(n is no of photon)

$n=27.2\times 10^{18}$

Hence (c) is the correct answer.

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