logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Atomic Structure

Calculate the velocity of an electron placed in $III$ orbit of H atom.Also calculate the no of revolution /sec round the nucleus.

$\begin{array}{1 1}(a)\;7.29\times 10^7cmsec^{-1}&(b)\;7.30\times 10^2cmsec^{-1}\\(c)\;8.39\times 10^7cmsec^{-1}&(d)\;7.29\times 10^3cmsec^{-1}\end{array}$

1 Answer

$\mu_n=\sqrt{\big(\large\frac{ze^2}{mr_n}\big)}$
Radius of $III$ orbit =$r_1\times n^2=0.529\times 10^{-8}\times 9cm$
$\mu_n=\sqrt{\big(\large\frac{1\times (4.083\times 10^{-10})^2}{9.108\times 10^{-28}\times 0.529\times 10^{-8}\times 9}\big)}$
$\mu_n=7.29\times 10^7cmsec^{-1}$
Hence (a) is the correct answer.
answered Jan 15, 2014 by sreemathi.v
 

Related questions

...