Email
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Calculate the wavelength of radiations emitted producing a line in Lyman series,when an electron falls from fourth stationary state in hydrogen atom $(R_H=1.1\times 10^7m^{-1})$

$\begin{array}{1 1}(a)\;1.34\times 10^{-7}m&(b)\;0.9696\times 10^{-7}m\\(c)\;1.34\times 10^{-4}m&(d)\;1.1\times 10^{-2}m\end{array}$

1 Answer

Comment
A)
$\large\frac{1}{\lambda}$$=R_H\bigg[\large\frac{1}{n_1^2}-\frac{1}{n_2^2}\bigg]$
$R_H=1.1\times 10^7$ for Lyman series $n_1=1$ and $n_2=4$ (Given)
$\therefore \large\frac{1}{\lambda}=$$1.1\times 10^7\bigg[\large\frac{1}{1^2}-\frac{1}{4^2}\bigg]$
$\lambda=0.9696\times 10^{-7}m$
Hence (b) is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
...