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Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Atomic Structure

Calculate the wavelength of moving electron having $4.55\times 10^{-25}$Joule of kinetic energy

$\begin{array}{1 1}(a)\;1.72\times 10^{-7}m&(b)\;7.27\times 10^{-2}m\\(c)\;7.27\times 10^{-7}m&(d)\;1.32\times 10^{-6}m\end{array}$

1 Answer

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Kinetic energy =$\large\frac{1}{2}$$mu^2=4.55\times 10^{-25}J$
$u^2=\large\frac{4.55\times 10^{-25}\times 2}{9.108\times 10^{-31}}$
$\therefore \lambda=\large\frac{h}{mu}$
$\Rightarrow \large\frac{6.625\times 10^{-34}}{9.108\times 10^{-31}}$
$\Rightarrow 7.27\times 10^{-7}m$
Hence (c) is the correct answer.
answered Jan 15, 2014 by sreemathi.v

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