$(a)\;6603A^{\circ}\qquad(b)\;7364^{\circ}\qquad(c)\;5462A^{\circ}\qquad(d)\;6963A^{\circ}$

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$E_3$ for H=$-2.41\times 10^{-21}erg$

$E_2$ for H=$-5.42\times 10^{-21}erg$

$\therefore$ For a jump from III to II shell

$\Delta E=E_3-E_2=\large\frac{hc}{\lambda}$

$\therefore \lambda=\large\frac{hc}{E_3-E_2}$

$\Rightarrow \large\frac{6.625\times 10^{-27}\times 3.0\times 10^{10}}{-2.41\times 10^{-12}+5.42\times 10^{-12}}$

$\Rightarrow 6602.9\times 10^{-8}$cm

$\Rightarrow 6602.9A^{\circ}$

Hence (a) is the correct answer.

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