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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

A pair of dice is thrown independently three times. The probability of getting a score of exactly 9 twice is

$\begin {array} {1 1} (A)\;\large\frac{1}{729} & \quad (B)\;\large\frac{8}{9} \\ (C)\;\large\frac{8}{729} & \quad (D)\;\large\frac{8}{243} \end {array}$

 

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1 Answer

Probability of getting score 9 in a single throw
$ = \large\frac{4}{36}$
$ = \large\frac{1}{9}$
Probability of getting score 9 exactly twice
$ = 3C_2 \times \bigg( \large\frac{1}{9} \bigg)^2 \times \large\frac{8}{9} $
$ = \large\frac{8}{243}$
answered Jan 15, 2014 by thanvigandhi_1
 

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