A pair of dice is thrown independently three times. The probability of getting a score of exactly 9 twice is

$\begin {array} {1 1} (A)\;\large\frac{1}{729} & \quad (B)\;\large\frac{8}{9} \\ (C)\;\large\frac{8}{729} & \quad (D)\;\large\frac{8}{243} \end {array}$

Probability of getting score 9 in a single throw
$= \large\frac{4}{36}$
$= \large\frac{1}{9}$
Probability of getting score 9 exactly twice
$= 3C_2 \times \bigg( \large\frac{1}{9} \bigg)^2 \times \large\frac{8}{9}$
$= \large\frac{8}{243}$